I'm not sure if that's the most relevant question. It seems @noione already has a certificate issued, as there is a /live/ directory containing a symlink to a private key.
@noione Could you tell us what you're actually trying to accomplish? Why are you trying to "validate" a CSR when you already have a certificate?
Also note: you've already got two certificates issued for your domain name. But you didn't include the www subdomain. Is that by choice? I see your "bare" domain hostname redirects to the www subdomain.
Also interesting: if you go to the https:// version of your website, which works like a charm, you have a redirect to the non HTTPS version of the www subdomain.
Where are you trying to add the domain name to? Like I said, your domain name already has a working HTTPS version, but is redirecting to a non-HTTPS version.
Hi @noione, the private key privkey.pem is not a CSR and should never be shared with anyone.
Can you explain more about your hosting situation and what name.com’s role is? Why do you need name.com to do anything, and what do you need them to do?
What I’m seeing right now is that coques-telephone.com has a valid certificate, although HTTP isn’t redirected to HTTPS. However, the certificate doesn’t cover www.coques-telephone.com (which it should). The process that obtained the certificate for coques-telephone.com should be able to obtain a certificate for both names.
Hi @schoen, thank you for the information sorry i’m novice,
i want to activate the SSL so all my pages will be redirected to HTTPS, name.com will validate the HTTPS with my domain name, because when i open my domain name the navigator show that the domain name doesn’t correspond to the certificat of my server
You have a correct certificate for coques-telephone.com but it doesn’t cover www.coques-telephone.com. It should. You should reissue your certificate so that it covers both names; then the error that you see about the mismatched name will go away.
After that, other web server configuration changes will also be necessary, but this is the first problem.